(20x^2-25x-30)/3x=(4x^2-28x+4)/3x+5

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Solution for (20x^2-25x-30)/3x=(4x^2-28x+4)/3x+5 equation: 



(20x^2-25x-30)/3x=(4x^2-28x+4)/3x+5

We move all terms to the left:

(20x^2-25x-30)/3x-((4x^2-28x+4)/3x+5)=0



Domain of the equation: 3x!=0

x!=0/3

x!=0

x∈R





Domain of the equation: 3x+5)!=0

x∈R



We calculate fractions

We do not support expression: x^3

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